Well, here is the formula:

So, when we personalize this to our dilemma, it is:

(((3 x HP Max - 2 x 1) x 3 x 2) / 3 x HP Max) x 2

Now - since you didn't give us the HP Max (a very important part of the equation) I will assume it's 150. I'll edit the answer once you give it to us, but just so you know. :3

Now the equation is:

(((3 x 150 - 2 x 1) x 3 x 2) / 3 x 150) x 2

3 x 150 (Maximum HP) = **450**

2 x 1 (Current HP) = **2**

450 - 2 = **448**

The equation is now:

((448 x 3 x 2) / 3 x 150) x 2

448 (number from previous bracket) x 3 (Base Catch Rate) = **1,344**

1,344 (number from above) x 2 (Ultra Ball) = **2,688**

The equation is now:

(2,688 / (3 x 150)) x 2

3 x 150 (Max HP) = **450**

The equation is now:

(2,688 / 450) x 2

2,688 / 450 (both numbers from previous equations) = **5.973333 (rounded to 6)**

6 (number from above) x 2 (SLP or FRZ) = *12*

So, the catch rate for the Pokemon with that criteria with the assumption of Max HP 150, the answer is **12.**

Hope I helped. :)