Meta Battle Subway PokeBase - Pokemon Q&A Login Register All Activity Questions Unanswered Tags Users Ask a Question Rules Chat Pokemon calculations to be solved? 2 votes 163 views These are several questions, I would like answers to all of them. What is the algorithm of meeting a Pokemon in the wild? What is the algorithm of meeting Pokemon in the wild with a specific nature? What is the algorithm of meeting Pokemon in the wild with a specific nature while having a Pokemon with Synchronize? What are the chances of meeting a shiny Pokemon with a specific ability (with two to choose from), a specific nature, 6 flawless IV:s and having a specific gender? Sorry for the trouble but I would like to know. Thank you in advance! algorithms chance calculate asked Oct 2, 2015 by Nr755 exelent question Thank you Try not to make it so obvious when you spam vote yourself. http://pokemondb.net/pokebase/user/Nr755/wall LOL! My younger brother knew I wanted to get to 1000 points, and he said he would help me in exchange for Nutella. I said Yes, of course. Guess I didn't think about how he would help me. Sorry fo the trouble, it wont happen again! Then explain why those accounts logged in immediately after you posted each of your last few questions and voted them? I don't believe that story, but whatever the case, it isn't allowed. We share a computer and have limited time so he probably just logged in after me, don't know for sure though. Also, if you're not allowed to have two accounts, then you should ban my second account Nr7555. Once again, sorry for the troubles! Please log in or register to add a comment. Please log in or register to answer this question. 1 Answer 3 votes Best answer The formula to meet a Pokemon in the wild is simply defined by P = x / 187.5. x is either 10 (Very common Pokemon), 8.5 (Common Pokemon), 6.75 (Semi-rare Pokemon), 3.33 (Rare Pokemon), or 1.25 (Very rare Pokemon). That gives either a 5.33%, 4.53%, 3.60%, 1.78%, or 0.67%, respectively. (Source) There are a total of 25 Natures, meaning the chance of encountering a Pokemon with a specific nature is 1/25, or 4%. So, multiplying the encounter rate by that factor will result in the equation P = x /4687.5. This will turn then abformentioned encounter rates into 0.21%, 0.18%, 0.14%, 0.07%, or 0.03%. Synchronize turns that 1/25 chance into a nifty 1/2 chance, which will greatly enhance the encounter rate. The formula now becomes P = x/375. The encounter rates now turn into 2.67%, 2.27%, 1.80%, 0.89%, or 0.33%. At this point, I have no idea why anyone would bother, but... Abililty: 1/2 Nature: 1/25 31 Flawless IVs: 1/(31)^6 Shiniess: Before Gen VI: 1/8192 | Gen VI: 1/4096 Gender: There are 6 different ratios: All male, 87.5% male, 12.5% female; 75% male, 25% female; 25% male, 75% male; 50% male, 50% female; all female. Crunch time. BEFORE GENERATION VI: All Male / All Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(1) = P = x/68160282700800000 (Male / Female) 75% Male, 25% Female: Male: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(3/4) -> P = x/90880376934400000 Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(1/4) -> P = x/272641130803200000 75% Female, 25% Male: Male: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(1/4) -> P = x/272641130803200000 Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(3/4) -> P = x/90880376934400000 87.5% Male, 12.5% Female: Male: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(7/8) -> P = 7x/545282261606400000 Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(1/8) -> P = x/545282261606400000 50% Male, 50% Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(1/2) - > P = x/136320565401600000 (Male / Female) GENERATION VI All Male / All Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(1) = P = x/34080141350400000 (Male / Female) 75% Male, 25% Female: Male: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(3/4) -> P = x/45440188467200000 Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(1/4) -> P = x/136320565401600000 75% Female, 25% Male: Male: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(1/4) -> P = x/136320565401600000 Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(3/4) -> P = x/45440188467200000 87.5% Male, 12.5% Female: Male: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(7/8) -> P = 7x/272641130803200000 Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(1/8) -> P = x/272641130803200000 50% Male, 50% Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(1/2) - > P = x/68160282700800000 (Male / Female) answered Oct 3, 2015 by Mewderator selected Oct 3, 2015 by Nr755 Didnt think that anyone would actually do it, so Thank You! 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