Meta Battle Subway PokeBase - Pokemon Q&A
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These are several questions, I would like answers to all of them.

What is the algorithm of meeting a Pokemon in the wild?
What is the algorithm of meeting Pokemon in the wild with a specific nature?
What is the algorithm of meeting Pokemon in the wild with a specific nature while having a Pokemon with Synchronize?
What are the chances of meeting a shiny Pokemon with a specific ability (with two to choose from), a specific nature, 6 flawless IV:s and having a specific gender?

Sorry for the trouble but I would like to know.

Thank you in advance!

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exelent question
Thank you
Try not to make it so obvious when you spam vote yourself.
http://pokemondb.net/pokebase/user/Nr755/wall
LOL! My younger brother knew I wanted to get to 1000 points, and he said he would help me in exchange for Nutella. I said Yes, of course. Guess I didn't think about how he would help me. Sorry fo the trouble, it wont happen again!
Then explain why those accounts logged in immediately after you posted each of your last few questions and voted them? I don't believe that story, but whatever the case, it isn't allowed.
We share a computer and have limited time so he probably just logged in after me, don't know for sure though. Also, if you're not allowed to have two accounts, then you should ban my second account Nr7555. Once again, sorry for the troubles!

1 Answer

3 votes
 
Best answer
  • The formula to meet a Pokemon in the wild is simply defined by P = x / 187.5. x is either 10 (Very common Pokemon), 8.5 (Common Pokemon), 6.75 (Semi-rare Pokemon), 3.33 (Rare Pokemon), or 1.25 (Very rare Pokemon). That gives either a 5.33%, 4.53%, 3.60%, 1.78%, or 0.67%, respectively. (Source)

  • There are a total of 25 Natures, meaning the chance of encountering a Pokemon with a specific nature is 1/25, or 4%. So, multiplying the encounter rate by that factor will result in the equation P = x /4687.5. This will turn then abformentioned encounter rates into 0.21%, 0.18%, 0.14%, 0.07%, or 0.03%.

  • Synchronize turns that 1/25 chance into a nifty 1/2 chance, which will greatly enhance the encounter rate. The formula now becomes P = x/375. The encounter rates now turn into 2.67%, 2.27%, 1.80%, 0.89%, or 0.33%.

  • At this point, I have no idea why anyone would bother, but...

  • Abililty: 1/2
  • Nature: 1/25
  • 31 Flawless IVs: 1/(31)^6
  • Shiniess: Before Gen VI: 1/8192 | Gen VI: 1/4096
  • Gender: There are 6 different ratios: All male, 87.5% male, 12.5% female; 75% male, 25% female; 25% male, 75% male; 50% male, 50% female; all female.

Crunch time.


BEFORE GENERATION VI:

  • All Male / All Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(1) = P = x/68160282700800000 (Male / Female)
  • 75% Male, 25% Female:
  • Male: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(3/4) -> P = x/90880376934400000
  • Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(1/4) -> P = x/272641130803200000
  • 75% Female, 25% Male:
  • Male: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(1/4) -> P = x/272641130803200000
  • Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(3/4) -> P = x/90880376934400000
  • 87.5% Male, 12.5% Female:
  • Male: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(7/8) -> P = 7x/545282261606400000
  • Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(1/8) -> P = x/545282261606400000
  • 50% Male, 50% Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/8192)(1/2) - > P = x/136320565401600000 (Male / Female)

GENERATION VI

  • All Male / All Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(1) = P = x/34080141350400000 (Male / Female)
  • 75% Male, 25% Female:
  • Male: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(3/4) -> P = x/45440188467200000
  • Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(1/4) -> P = x/136320565401600000
  • 75% Female, 25% Male:
  • Male: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(1/4) -> P = x/136320565401600000
  • Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(3/4) -> P = x/45440188467200000
  • 87.5% Male, 12.5% Female:
  • Male: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(7/8) -> P = 7x/272641130803200000
  • Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(1/8) -> P = x/272641130803200000
  • 50% Male, 50% Female: P = (x / 187.5)(1/2)(1/25)(1/(31)^6)(1/4096)(1/2) - > P = x/68160282700800000 (Male / Female)
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Didnt think that anyone would actually do it, so Thank You!