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What are the odds of finding a horde with 5 shinies that all have 6 perfect IVs and pokerus?

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Probably close to 0%.
Shame you would have to faint all other ones before catching the last one. :P
0% must be too high :P
And y was this flagged?
I don't know I didn't break any rules
-infinity%
I got this, guys.
Answered. Easy as pi.

1 Answer

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Best answer

There are 32 possible values (0-31) for each of the 6 stats, which makes it 1 in 32^6 or 1 in 1,073,741,824! Source.

The shiny chance in X & Y is 1/4096

Pokérus has a 3/65,536 or approximately a 1 in 21,845 chance of being generated on a Pokémon, either wild or bred. Source.


First, we find the chance of having Pokerus and 31 IVs on a Pokemon, which is
(1/1073741824 * 3/65536) = 3/70368744177664

and multiply that by the shiny chance,

(3/70368744177664 * 1/4096) = 3/288230376151711744

and gather five of these Pokemon together in a horde, and with generous rounding we get:

(3/288230376151711744)^5 = 243/19892929456391465686215289925873000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
which equates to roughly
.000000000000000000000000000000000000000000000000000000000000000000000000000000000000012215395451569638936599271271031%.

No, I am not kidding.

Source: Calculations and above sources.

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Mind blown
Good job answering