#720 actually.

The formula you should be using is this;

nPr, meaning n!/(n-r)!

n represents the amount of values, and r represents the amount of values that you actually take. Since in this case, you have 6 values, **but you take all 6**. The formula nPr is used when order matters and repetition is not allowed.

**What do I mean by order mattering?**

If order **does not matter** the combination [3,23,62] would be the same as [23,3,62]

However when **order does matter** the combination [3,23,62] would be different from [23,3,62]

So subbing this into the formula

= 6!/(6-6)!

**Please note that ! in maths represents "Factorial" - this means you must multiply the number by every single positive integer under it, not including 0 since that technically isn't either positive nor negative e_o**

= 720/0! (0! is equal to 1. This is the exception to the explanation I gave above about !)

= 720

Well, Jojo tested this on your calculator and I think we know the source of your problem now

**There are two 65s, so the online calculator factors them as "duplicates"**

## Extra Stuff

>If you factor in types, allowing dual types, would that restrict the number?

hmmm...

Just wondering

aren't there 18 types...

commented 15 hours ago by Helios_Ex

If we were to take dual types, then the amount of possible eeveelutions that are possible is equivalent to the amount of possible dual types + amount of possible single types.

What is this?

6P2 + 18

= 153 + 18

= 171

So if we were to factor in types, allowing dual types, top of 171 eeveelutions.