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In the best scenario possible, a Pokémon is frozen, confused, and under the effects of attract. Instead of rock slide spam a kings rock maushold is instructed to attack our dummy twice (hitting all 10 hits both times), kings rock gives this a higher flinch chance than rock slide. And for absolute maximum modifiers the frozen Pokemons partner is a king's rock maushold which happens to attack it and hit all 10.

After:
Unfreezing
No Confusion
No Attraction
Not Flinching to Pop Bomb
Not Flinching to Pop Bomb
Not Flinching to Pop Bomb

What is the chance of this happening?

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Whats the point of this question? There is no way you’re actually going to be able to recreate this in a real game.
The more you know
this is insane
I don't actually think this is possible because maushold can't learn attract. I know what you said earlier, I just wanted to point it out.
It doesn't need to be Maushold with attract, if it's a double battle. This scenario already establishes that we need an Oranguru partner for Instruct on Pop Bomb, which can also learn Attract.

1 Answer

2 votes

In this setup, we're assuming that it's Oranguru and Maushold (holding King's Rock) vs Oranguru and our target Pokémon. The target is frozen, confused, and infatuated with the opposing Oranguru (since Maushold cannot learn Attract). Maushold uses Population Bomb on the target and lands all 10 hits, then both the ally and opposing Oranguru use Instruct on Maushold, and both of the following Population Bombs also land all 10 hits. Assuming all the above happens (we will not be considering the odds of these Pop Bombs all landing), the target Pokémon then moves last, and we want to know the odds of it successfully landing a hit.

In Champions, a Pokémon that is frozen has a 1/4 chance of thawing on each of the first two turns, and a 100% chance of thawing on turn 3. We'll assume that the Pokémon has been frozen for less than 2 turns.

Pokémon that are confused have a 1/3 chance of hitting itself, and a 2/3 chance of moving normally.

Pokémon that are infatuated have a 50% chance of moving or being immobilized.

Each hit of Population Bomb has a 10% flinch chance, and we've landed it 30 times. The chance of it not flinching 30 times in a row is (9/10)^30, which is a 4.23911583% chance, or about 1 / 23.6.

Now we just multiply the odds of moving at each stage together:
1/4 * 2/3 * 1/2 * 1/23.5898249 = 0.353259652%, or about 1 / 283

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