### TL;DR: very very bad.

Stakataka has three of six IVs that are guaranteed to be perfect. 3 IVs * 6 IVs = **18 different ways** the Pokemon can have three randomly-generated perfect IVs. They are listed here, assuming *x* is a random value:

```
31/31/31/x/x/x
31/31/x/31/x/x <--- this works if the first x is 15, the second x to last is 31 and the last x is 0
31/31/x/x/31/x <--- this works if the first x is 15 and the last x is 0; lacks perfect SAtk
31/31/x/x/x/31
31/x/31/31/x/x
31/x/x/31/31/x <--- this works if the first x is 31, the second x is 15 and the last x is 0
31/x/x/x/31/31
x/31/31/31/x/x
x/x/31/31/31/x
x/x/x/31/31/31
x/x/31/x/31/31
x/31/x/x/31/31
x/31/x/31/x/31
x/31/31/x/x/31
x/31/31/x/31/x
31/x/31/x/31/x
31/x/x/31/x/31
x/x/31/31/x/31
```

We'll call the **three possibilities** that would work possibilities *a*, *b* and *c*. We'll calculate them one-by-one:

For *a*, 1/18 perfect IV options would suffice, and you'd need a 1/32 chance to go in your favour three times. You'd also need the coin toss for Synchronise to work. So:

*Pr(a)* = 1/18 * 1/32 * 1/32 * 1/32 * 1/2 = 1/1179648

For *b*, 1/18 perfect IV options would suffice, and you'd need a 1/32 chance to go in your favour twice. You'd also need the coin toss for Synchronise to work. So:

*Pr(b)* = 1/18 * 1/32 * 1/32 * 1/2 = 1/36864

If you're really going for the imperfect SAtk IV, you'll need to add an extra 31/32 chance (we'll call this *bA*):

*Pr(bA)* = 1/18 * 1/32 * 1/32 * 31/32 * 1/2 = 31/1179648 or roughly 1/38053

For *c*, 1/18 perfect IV options would suffice, and you'd need a 1/32 chance to go in your favour three times. You'd also need the coin toss for Synchronise to work. So it's the same as *a*:

*Pr(c)* = 1/18 * 1/32 * 1/32 * 1/32 * 1/2 = 1/1179648

So your chances will be as follows:

First, if you'll allow the SAtk IV to be of any value:

*Pr(a + b + c)* = 1/1179648 + 1/36864 + 1/1179648 = 17/589824 or roughly **1/34696**

Second, if you'll only allow the SAtk IV to be imperfect. You will only accept option *bA*. So your chance is:

*Pr(bA)* = 1/18 * 1/32 * 1/32 * 31/32 * 1/2 = 31/1179648 or roughly **1/38053**

If you want these rarities in context, the first option is **over eight times rarer than finding a random Shiny**, and the second over nine times rarer. Long story short, you'll be sat down soft resetting for a very long time if you want this particular Pokemon. :P